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JIPMER 2009
Exam
JIPMER
Year
2009
Subject
Chemistry
Chapter
States of Matter

JIPMER 2009 · Chemistry · States of Matter

The most probable velocity (in cm / s ) of hydrogen molecule at 27^...

The most probable velocity (in cm/s\mathrm{cm} / \mathrm{s} ) of hydrogen molecule at 27∘C27^{\circ} \mathrm{C} will be

Options

  1. A19.3×10419.3 \times 10^4
  2. B17.8×10417.8 \times 10^4
  3. C24.93×10924.93 \times 10^9
  4. D17.8×10817.8 \times 10^8

Correct answer

B. 17.8×10417.8 \times 10^4

Step-by-step solution

 Most probable velocity =8RTπmT=(27+273)=300K Molecular mass of H2=2gmol−1=8×8.314×107×3003.14×2=17.8×104cm/s. \begin{aligned} & \text{ Most probable velocity }=\sqrt{\frac{8 R T}{\pi m}} \\ & T=(27+273)=300 \mathrm{ K} \\ & \text{ Molecular mass of } \mathrm{H}_2=2 \mathrm{ g} \mathrm{ mol}^{-1} \\ & =\sqrt{\frac{8 \times 8.314 \times 10^7 \times 300}{3.14 \times 2}} \\ & =17.8 \times 10^4 \mathrm{ cm} / \mathrm{s} \text{. } \\ & \end{aligned}
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