NEET2009ChemistryStates of MatterActual
The mean free path of electrons in a metal is 4 10⁻⁸ ~m . The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V / m :
Options
- A5 10^7
- B8 10^7
- C5 10⁻¹¹
- D8 10⁻¹¹
Correct answer
A. 5 10^7
Step-by-step solution
aligned qV & =2 eV 1.6 10⁻¹⁹ ~V & =2 1.6 10⁻¹⁹ ~V V & =2 ~V E & = V d E & = 2 ~V 4 10⁻⁸ =5 10^7 aligned