A gas mixture contains (O_2) and (N_2) in the ratio of 1: 4 by weight. The ratio of their number of molecules is

Correct answer: D. 7: 32 ( ) The ratio of ( O _ 2 ) and (N _ 2 ) by weight is 1: 4 . ( ) the ratio of ( O _ 2 ) and (N _ 2 ) by moles (= (1)/(32) : (4)/(28) ) =7: 32

JIPMER 2008

Exam: JIPMER
Year: 2008
Subject: Chemistry
Chapter: States of Matter

JIPMER 2008 · Chemistry · States of Matter

A gas mixture contains (O_2) and (N_2) in the ratio of 1: 4 by...

A gas mixture contains (\mathrm{O}_2) and (\mathrm{N}_2) in the ratio of

1: 4

by weight. The ratio of their number of molecules is

Options

A $1: 8$
B $1: 4$
C $3: 16$
D $7: 32$

Correct answer

D. $7: 32$

Step-by-step solution

(\because) The ratio of (

\mathrm{O}}_{2}) and (\mathrm{N}

}_{2}) by weight is

1: 4

. (\therefore) the ratio of (

\mathrm{O}}_{2}) and (\mathrm{N}

}_{2}) by moles (=

\frac{1}{32}

\frac{4}{28}

)

=7: 32

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