JIPMER2008ChemistryStates of Matter
The volume of a gas measured at (27^ C ) and 1 atm pressure is 10 L. To reduce the volume to 2 L at 1 atm pressure, the temperature required is
Options
- A60 K
- B75 K
- C150 K
- D225 K
Correct answer
A. 60 K
Step-by-step solution
Here ( aligned & V₁=10 ~L , V₂=2 ~L & p₁=1 ~atm , p₂=1 ~atm aligned ) ( gathered T₁=300 ~K , T₂=? p₁ V₁ T₁ = p₂ V₂ T₂ 1 10 300 = 1 2 T₂ T₂= 300 2 10 =60 ~K gathered )