The volume of a gas measured at (27^ C) and 1 atm pressure is 10 L....

Here $$\begin{aligned} & V_1=10 \mathrm{~L}, V_2=2 \mathrm{~L} \\ & p_1=1 \mathrm{~atm}, p_2=1 \mathrm{~atm} \end{aligned}$$) (\begin{gathered}T_1=300 \mathrm{~K}, T_2=? \\ \frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2} \\ \frac{1 \times 10}{300}=\frac{1 \times 2}{T_2} \\ T_2=\frac{300 \times 2}{10}=60 \mathrm{~K}\end{gathered})$