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JIPMER 2004
Exam
JIPMER
Year
2004
Subject
Physics
Chapter
Alternating Current

JIPMER 2004 · Physics · Alternating Current

The peak value of alternating current is 5 2 ampere. The mean...

The peak value of alternating current is 525 \sqrt{2} ampere. The mean square value of current will be

Options

  1. A55 A
  2. B2.52.5 A
  3. C525 \sqrt{2}
  4. DNone of the above

Correct answer

A. 55 A

Step-by-step solution

Here: I0=52 AI_0=5 \sqrt{2} \mathrm{~A} Root mean square value of current Irms=I02=522=5 AI_{\mathrm{rms}}=\frac{I_0}{\sqrt{2}} = \frac{5 \sqrt{2}}{\sqrt{2}}=5 \mathrm{~A}
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