JIPMER2004PhysicsAlternating Current
The peak value of alternating current is 5 2 ampere. The mean square value of current will be
Options
- A5 A
- B2.5 A
- C5 2
- DNone of the above
Correct answer
A. 5 A
Step-by-step solution
Here: I₀=5 2 ~A Root mean square value of current I_ rms = I₀ 2 = 5 2 2 =5 ~A