Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JIPMER2004PhysicsAlternating Current

A lamp in which 10 amp current can flow at 15 V, is connected with an alternating source of potential 220 V. The frequency of source is 50 Hz. The inductance of choke coil required to light the bulb is

Options

  1. A0.07 H
  2. B0.14 H
  3. C0.28 H
  4. D1.07 H

Correct answer

A. 0.07 H

Step-by-step solution

The resistance of lamp R= V I = 15 10 =1.5 The impedance of circuit Z= V I = 220 10 =22 ohm Again impedance Z= R^2+ ^2 L^2 or 22= (1.5)^2+(2 50)^2 L^2 or (22)^2=(1.5)^2+4 ^2 50^2 L^2 or L=0.07 Henry

Practice Alternating Current on Quantrex Academy →

More from Alternating Current

A step down transformer connected to an a.c. mains of 220 V is made to operate at 5.5 V, 44 W lamp. The current in the primary circuit is (Ignore power losses) 2026Which phasor diagram represents LCR circuit at resonance? 2026For an R-L series circuit, the power factor is 3 2 , for R-L frequency f Hz. If the frequency doubles, the new power factor will be 2026In an AC circuit, the current is I = 100 (5t) A. The value of I_ rms is 2026The ratio of power factor of purely resistive circuit to purely reactive circuit is ( 0^ = 1 and 90^ = 0 ) 2026In an LCR series circuit, at resonance, 2026In an AC circuit, E and I are given by E = 150 (150t) V and I = 150 (150t + 3 ) A. The power dissipated in the circuit is (60)^ = 1/2 2026A series LCR circuit is connected across a source E of e.m.f. E=15 (50 t- 3 ) . The current from the supply is I=5 (50 t+ 6 ) . The impedance of the circuit and the phase differenc 2026 Full Alternating Current list All JIPMER PYQs