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JIPMER 2018
Exam
JIPMER
Year
2018
Subject
Physics
Chapter
Alternating Current

JIPMER 2018 · Physics · Alternating Current

In a L-C circuit, angular frequency at resonance is ω . What will...

In a L-C circuit, angular frequency at resonance is ω\omega. What will be the new angular frequency when inductor's inductance is made two times and capacitor's capacitance is made four times?

Options

  1. Aω22\frac{\omega}{2 \sqrt{2}}
  2. Bω2\frac{\omega}{\sqrt{2}}
  3. C2ω2 \omega
  4. D2ω2\frac{2 \omega}{\sqrt{2}}

Correct answer

A. ω22\frac{\omega}{2 \sqrt{2}}

Step-by-step solution

∵\because Angular frequency at resonance, ω=1LC\omega=\frac{1}{\sqrt{\mathrm{LC}}} ...(i) According to question, when inductor's inductance is made 2 times and capacitance is 4 times, then ω′=1LC\omega^{\prime}=\frac{1}{\sqrt{\mathrm{LC}}} or ω′=(122)1LC\quad \omega^{\prime}=\left(\frac{1}{2 \sqrt{2}}\right) \frac{1}{\sqrt{\mathrm{LC}}} =ω22=\frac{\omega}{2 \sqrt{2}} \quad [From Eq. (i)]
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