NEET2018PhysicsAlternating CurrentActual
The magnetic potential energy stored in a certain inductor is 25   mJ , when the current in the inductor is 60   mA . This inductor is of inductance
Options
- A1 . 389   H
- B138 . 88   H
- C0.138   H
- D13.89   H
Correct answer
D. 13.89   H
Step-by-step solution
For current I through an inductor coil having inductance L , Magnetic potential energy stored in the inductor is given by U = 1 2 L I 2 Given U=25 mJ=25×10 - 3  J I=60 mA =60×10 - 3  A ∴     25 × 10 - 3 = 1 2 L 60 × 10 - 3 2 Solving L = 13.89   H