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JIPMER 2010
Exam
JIPMER
Year
2010
Subject
Physics
Chapter
Capacitance

JIPMER 2010 · Physics · Capacitance

Three capacitors of capacitances 1 μ F, 2 μ F and 4 μ F are...

Three capacitors of capacitances 1μF,2μF1 \mu \mathrm{F}, 2 \mu \mathrm{F} and 4μF4 \mu \mathrm{F} are connected first in a series combination, and then in a parallel combination. The ratio of their equivalent capacitances will be

Options

  1. A2:49
  2. B49:2
  3. C4:49
  4. D49:4

Correct answer

C. 4:49

Step-by-step solution

In series combination, 1C1=11+12+14=4+2+14=74⇒C1=47μF\frac{1}{C_1}=\frac{1}{1}+\frac{1}{2}+\frac{1}{4}=\frac{4+2+1}{4}=\frac{7}{4} \Rightarrow \quad C_1=\frac{4}{7} \mu \mathrm{F} In parallel combination, C1=1+2+4=7μF∴C1C2=4/77=449\begin{aligned} & C_1=1+2+4=7 \mu \mathrm{F} \\ \therefore \quad & \frac{C_1}{C_2}=\frac{4 / 7}{7}=\frac{4}{49} \end{aligned}
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