NEET2010PhysicsCapacitanceActual
A condenser of capacity C is charged to a potential difference of V₁ . The plates of the condenser are then connected to an ideal inductor of inductance L . The current through the inductor when the potential difference across the condenser reduces to V₂ is
Options
- A( C ( V ₁- V ₂ )^2 ~L )^ 1 2
- BC ( V ₁^2- V ₂^2 ) L
- CC ( V ₁^2+ V ₂^2 ) L
- D( C ( V ₁^2- V ₂^2 ) L )^ 1 2
Correct answer
D. ( C ( V ₁^2- V ₂^2 ) L )^ 1 2
Step-by-step solution
( aligned & CV ^2 2 + 1 2 Li ^2= constant & Initially i =0, ~V = V ₁ & Total energy = 1 2 CV ₁^2 & ~When V V ₂ & 1 2 C ( V ₂ )^2+ 1 2 Li ^2= 1 2 CV ₁^2 & Li ^2= C ( V ₁^2- V ₂^2 )^2 & i ^2= C L ( V ₁^2- V ₂^2 ) & i = C L ( V ₁^2- V ₂^2 ) aligned )