A galvanometer of 50 resistance has 25 divisions. A current of 4 ×...

A galvanometer of

50 \Omega

resistance has 25 divisions. A current of

4 \times 10^{-4}

A gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 V , it should be connected with a resistance of

Options

A $2500 \Omega$ as a shunt
B $245 \Omega$ as a shunt
C $2550 \Omega$ in series
D $2450 \Omega$ in series

Correct answer

D. $2450 \Omega$ in series

Step-by-step solution

Given, resistance of galvanometer

\left(\mathrm{R}_{\mathrm{g}}\right)=50 \Omega

Number of divisions

=25

\mathrm{I}

_{\mathrm{g}}=4 \times 10^{-4} \times 25=10^{-2} \mathrm{ A} R is the resistance connected in series of galvanometer to convert into voltmeter

\begin{aligned} \therefore V & =I_g\left(R_g+R\right) \\ 25 & =10^{-2}(50+R) \\ \Rightarrow R & =\frac{25}{10^{-2}}-50=2500-50 \Rightarrow R=2450 \Omega \text{ in } \end{aligned}

$$ series.

Practice Current Electricity on Quantrex Academy →

More from Current Electricity