Find the current in the 8 resistance in the given circuit.

The circuit can be redrawn as So, the circuit is break in two parts. As the other end of $8 \Omega$ resistor is grounded, is at zero potential, the potential difference across $8 \Omega$ resistor $=24-0=24 \mathrm{~V}$ So, current in $8 \Omega$ resistor $\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{24-0}{8}=3 \mathrm{~A}$.