JIPMER2016PhysicsCurrent Electricity
Two batteries of emf 3 V and 6 V with internal resistances 2 and 4 are connected in a circuit with resistance of 10 as shown in figure. The current and potential difference between the points P and Q are
Options
- A3 16 ~A and 8 15 ~V
- B16 3 ~A and 15 8 ~V
- C3 16 ~A and 8 V
- D3 16 ~A and 15 8 ~V
Correct answer
D. 3 16 ~A and 15 8 ~V
Step-by-step solution
Applying Kirchhoff's voltage law in the given loop, aligned -4 I+6-3-2 I-10 I & =0 -16 I & =-3 I & = 3 16 ~A aligned Potential difference across P Q= 3 16 10= 15 8 ~V