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JIPMER 2019
Exam
JIPMER
Year
2019
Subject
Physics
Chapter
Current Electricity

JIPMER 2019 · Physics · Current Electricity

A circuit contain two resistance R_1 and R_2 in series. Find the...

A circuit contain two resistance R1R_1 and R2R_2 in series. Find the ratio of input voltage to voltage of R2\mathrm{R}_2.A circuit contain two resistance R_1 and R_2 in series. Find the ratio of input voltage to voltage of R_2 .

Options

  1. AR2R1+R2\frac{R_2}{R_1+R_2}
  2. BR1+R2R2\frac{R_1+R_2}{R_2}
  3. CR1+R2R1\frac{R_1+R_2}{R_1}
  4. DR1R1+R2\frac{R_1}{R_1+R_2}

Correct answer

B. R1+R2R2\frac{R_1+R_2}{R_2}

Step-by-step solution

The situation is shown in the circuit diagram. A circuit contain two resistance R_1 and R_2 in series. Find the ratio of input voltage to voltage of R_2 . Current flowing through the circuit, I=ViR1+R2I=\frac{V_i}{R_1+R_2} Voltage across R2,V2=R2,V2=ViR2R1+R2R_2, V_2=R_2, V_2=\frac{V_i R_2}{R_1+R_2} ⇒R1+R2R2=ViV2⇒ViV2=R1+R2R2\Rightarrow \quad \frac{R_1+R_2}{R_2}=\frac{V_i}{V_2} \Rightarrow \frac{V_i}{V_2}=\frac{R_1+R_2}{R_2}
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