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JIPMER 2014
Exam
JIPMER
Year
2014
Subject
Physics
Chapter
Dual Nature of Matter

JIPMER 2014 · Physics · Dual Nature of Matter

Relation between wavelength of photon and electron of same energy is

Relation between wavelength of photon and electron of same energy is

Options

  1. Aλph>λe\lambda_{p h}\gt\lambda_e
  2. Bλph<λe\lambda_{p h} \lt \lambda_e
  3. Cλph=λe\lambda_{p h}=\lambda_e
  4. Dλeλph=\frac{\lambda_e}{\lambda_{p h}}= constant

Correct answer

A. λph>λe\lambda_{p h}\gt\lambda_e

Step-by-step solution

 Wavelength λ=hcp∴λ=hc2mE∴λ∝1m\begin{aligned} & \text{ Wavelength } \lambda=\frac{h c}{p} \\ & \therefore \quad \lambda=\frac{h c}{\sqrt{2 m E}} \therefore \lambda \propto \frac{1}{\sqrt{m}} \\ & \end{aligned} Mass of photon is less than that of electron. ∴\therefore Wavelength of photon is greater than that of electron λph>λe\lambda_{p h}>\lambda_e.
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