NEET2014PhysicsDual Nature of MatterActual
If the kinetic energy of the particle is increased to 16 times its previous value, the percentage change in the de-Broglie wavelength of the particle is:
Options
- A25
- B75
- C60
- D50
Correct answer
B. 75
Step-by-step solution
K E f i n a l = 16 K E i n i t i a l ⇒ 1 2 m v f 2 = 16 × 1 2 m v i 2 (mass remains same because the particle remains same) ⇒ v f = 4 v i We know that, De-broglie wavelength ( λ ) = h m v ∴ λ f = h m v f = h 4 m v i So De-Broglie wave will decreased to 75 %