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JIPMER2015PhysicsElectrostatics

Two charges of +10 C and +20 C are separated by a distance 2 cm . The net potential (electric) due to the pair at the middle point of the line joining the two changes, is

Options

  1. A27 MV
  2. B18 MV
  3. C20 MV
  4. D23 MV

Correct answer

A. 27 MV

Step-by-step solution

Using the equation V= Q 4 ₀ I The potential due to +10 C is V₁= (10 10⁻⁶ ) (9 10^9 ) 1 10⁻² =9 MV The potential due to +20 C is V₂= 20 10⁻⁶ 9 10^9 1 10⁻² =18 MV The net potential at the given point is 9 MV +18 MV =27 MV

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