Three equal charges, each having a magnitude of 2.0 10⁻⁶ C , are placed at the three corners of a right angled triangle of sides 3 ~cm , 4 ~cm and 5 cm . The force (in magnitude) on the charge at the right angled corner is

Step-by-step solution

Consider the diagram The situation is shown in figure. The force on A due to B is F₁= (2.0 10⁻⁶ ) (2.0 10⁻⁶ ) 4 ₀(4 ~cm )^2 aligned =9 10^9 4 10⁻¹² & 1 16 10⁻⁴ & =22.5 ~N aligned As the force due to C on A is 40 N . Thus, net force (electric) aligned F & = F₁^2+F₁^2 & = (22.5)^2+(40)^2 =45.9 ~N aligned