R =65 1 L , l =5 0.1 ~mm and d =10 0.5 ~mm . Find error in calculation of resistivity.

Step-by-step solution

Given that, R =65 , R =1 , l =5 10⁻³ ~m , l =0.1 10⁻³ ~m , ~d =10 10⁻³ ~m , d =0.5 10⁻³ ~m Resistivity, = R A l or = R ( d / 2)^2 l = Rd ^2 4 l array ll & = R R +2 d d + l l & = 1 65 +2 ( 0.5 10⁻³ 10 10⁻³ )+ 0.1 10⁻³ 5 10⁻³ array or =0.0153+0.1+0.02 or 0.1353 So, error in calculation of resistivity is 13.5 % 13 % .