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JIPMER 2014
Exam
JIPMER
Year
2014
Subject
Physics
Chapter
Motion in One Dimension

JIPMER 2014 · Physics · Motion in One Dimension

A particle moves towards east for 2 s with velocity 15 ~m / s and...

A particle moves towards east for 2 s with velocity 15 m/s15 \mathrm{~m} / \mathrm{s} and move towards north for 8 s with velocity 5 m/s5 \mathrm{~m} / \mathrm{s}. Then, average velocity of the particle is

Options

  1. A1 m/s1 \mathrm{~m} / \mathrm{s}
  2. B5 m/s5 \mathrm{~m} / \mathrm{s}
  3. C7 m/s7 \mathrm{~m} / \mathrm{s}
  4. D10 m/s10 \mathrm{~m} / \mathrm{s}

Correct answer

B. 5 m/s5 \mathrm{~m} / \mathrm{s}

Step-by-step solution

Distance covered towards east =2×15=30 m=2 \times 15=30 \mathrm{~m} Distance covered towards north =8×5=40 m=8 \times 5=40 \mathrm{~m} Total displacement =402+302=50 m=\sqrt{40^2+30^2}=50 \mathrm{~m} Average velocity = Total displacement  Total time =502+8=5 m/s\begin{aligned} \text{ Average velocity } & =\frac{\text{ Total displacement }}{\text{ Total time }} \\ & =\frac{50}{2+8}=5 \mathrm{~m} / \mathrm{s}\end{aligned}$$
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