Speeds of a particle at 3rd and 8th sec are 20 ~m / s and zero respectively, then average acceleration between 3 rd and 8th sec will be

Correct answer: B. 4 ~m / s^2 Time interval between 8 th sec. and 3rd sec Δ t=8-3=5 ~s i.e. Δ t=5 ~s Change in velocity Δ V=20-0=20 ~m / s Average acceleration = Δ V Δ t =(20)/(5)=4 ~m / s^2

JIPMER 2019

Exam: JIPMER
Year: 2019
Subject: Physics
Chapter: Motion in One Dimension

JIPMER 2019 · Physics · Motion in One Dimension

Speeds of a particle at 3rd and 8th sec are 20 ~m / s and zero...

Speeds of a particle at 3rd and 8th sec are

20 \mathrm{~m} / \mathrm{s}

and zero respectively, then average acceleration between 3 rd and 8th sec will be

Options

A $3 \mathrm{~m} / \mathrm{s}^2$
B $4 \mathrm{~m} / \mathrm{s}^2$
C $5 \mathrm{~m} / \mathrm{s}^2$
D $6 \mathrm{~m} / \mathrm{s}^2$

Correct answer

B. $4 \mathrm{~m} / \mathrm{s}^2$

Step-by-step solution

Time interval between 8 th sec. and 3rd sec

\Delta \mathrm{t}=8-3=5 \mathrm{~s}

i.e.

\Delta t=5 \mathrm{~s}

Change in velocity

\Delta \mathrm{V}=20-0=20 \mathrm{~m} / \mathrm{s}

\therefore

Average acceleration

=\frac{\Delta \mathrm{V}}{\Delta \mathrm{t}}=\frac{20}{5}=4 \mathrm{~m} / \mathrm{s}^2

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