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JIPMER 2012
Exam
JIPMER
Year
2012
Subject
Physics
Chapter
Motion in One Dimension

JIPMER 2012 · Physics · Motion in One Dimension

A police party is moving in a jeep at a constant speed v . They saw...

A police party is moving in a jeep at a constant speed vv. They saw a thief at a distance xx on a motorcycle which is at rest. The moment the police saw the thief, the thief started at constant acceleration aa. Which of the following relations is true if the police is able to catch the thief?A police party is moving in a jeep at a constant speed v . They saw a thief at a distance x on a motorcycle which is at

Options

  1. Av2<axv^2 \lt a x
  2. Bv2<2axv^2 \lt 2 a x
  3. Cv2≥2axv^2 \geq 2 a x
  4. Dv2=axv^2=a x

Correct answer

C. v2≥2axv^2 \geq 2 a x

Step-by-step solution

Let the police party catch the thief after t st \mathrm{~s} ∴\therefore Distance travelled by police party in t s=vtt \mathrm{~s}=v t and distance travelled by thief =x+12αt2=x+\frac{1}{2} \alpha t^2 A police party is moving in a jeep at a constant speed v . They saw a thief at a distance x on a motorcycle which is at So, x+12αt2≤vt\quad x+\frac{1}{2} \alpha t^2 \leq v t or αt22−vt+x=0\quad \frac{\alpha t^2}{2}-v t+x=0 or t=v±v2−2αxα\quad t=\frac{v \pm \sqrt{v^2-2 \alpha x}}{\alpha} For tt to be real, v2≥2αxv^2 \geq 2 \alpha x
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