If we throw a body upwards with velocity of 4 ~m / s , at what height does its kinetic energy reduce to half of the initial value? (Take g=10 ~ms ⁻² )

Step-by-step solution

Key Idea : At a given height the half of the kinetic energy of the body is equal to its potential energy. Initial kinetic energy of the body aligned & = 1 2 m v^2 & = 1 2 m(4)^2=8 m aligned Let at height h , the kinetic energy reduces to half, ie, it becomes 4 m . It is also equal to potential energy. Hence, m g h=4 ~m or h= 4 g = 4 10 =0.4 ~m