JIPMER2010PhysicsNuclear Physics
If ₉₂ U ²³⁸ emits 8 -particles and 6 -particles, then the resulting nucleus is
Options
- A₈₂ U ²⁰⁶
- B₈₂ ~Pb ²⁰⁶
- C₈₂ U ²¹⁰
- D₈₂ U ²¹⁴
Correct answer
B. ₈₂ ~Pb ²⁰⁶
Step-by-step solution
After one -emission, the daughter nucleus reduces in mass number by 4 unit and in atomic number by 2 unit. In -emission the atomic number of daughter nucleus increases by 1 unit. The reaction can be written as ₉₂ U ²³⁸ -8 ₇₆ X²⁰⁶ -6 ₈₂ Y²⁰⁶ Thus, the resulting nucleus is ₈₂ Y²⁰⁶, i e, ₈₂ ~Pb ²⁰⁶ .