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JIPMER 2016
Exam
JIPMER
Year
2016
Subject
Physics
Chapter
Nuclear Physics

JIPMER 2016 · Physics · Nuclear Physics

If a proton and anti-proton come close to each other and...

If a proton and anti-proton come close to each other and annihilate, how much energy will be released?

Options

  1. A1.5×10−10 J1.5 \times 10^{-10} \mathrm{~J}
  2. B3×10−10 J3 \times 10^{-10} \mathrm{~J}
  3. C4.5×10−10 J4.5 \times 10^{-10} \mathrm{~J}
  4. D2×10−10 J2 \times 10^{-10} \mathrm{~J}

Correct answer

B. 3×10−10 J3 \times 10^{-10} \mathrm{~J}

Step-by-step solution

Mass of proton = mass of anti-proton =1.67×10−27 kg=1amu=1.67 \times 10^{-27} \mathrm{~kg}=1 \mathrm{amu} Energy equivalent to 1amu=931MeV1 \mathrm{amu}=931 \mathrm{MeV}. So, energy equivalent to 2amu=2×931MeV2 \mathrm{amu}=2 \times 931 \mathrm{MeV}=1862×106×1.6×10−19=2.97×10−10 J=3×10−10 J\begin{aligned} & =1862 \times 10^6 \times 1.6 \times 10^{-19} \\ & =2.97 \times 10^{-10} \mathrm{~J} \\ & =3 \times 10^{-10} \mathrm{~J}\end{aligned}$$
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