In the reaction given below _ 86 A^ 222 _ 84 B^ 210 how many α and β -particles are emitted?

Correct answer: B. 3 α, 4 β _ 86 A^ 222 _ 84 B^ 210 aligned Decrease in mass number & =222-210 & =12 aligned Number of α -particles emitted aligned & =(12)/(4)=3 _ 86 A^ 222 _ 80 X^ 210 & 84 B^ 210 aligned Increase in atomic number =84-80=4 Number of β -particles emitted =4

JIPMER 2006

Exam: JIPMER
Year: 2006
Subject: Physics
Chapter: Nuclear Physics

JIPMER 2006 · Physics · Nuclear Physics

In the reaction given below _ 86 A^ 222 _ 84 B^ 210 how many α and...

In the reaction given below

{ }_{86} A^{222} \longrightarrow{ }_{84} B^{210}

how many

\alpha

and

\beta

-particles are emitted?

Options

A $6 \alpha, 3 \beta$
B $3 \alpha, 4 \beta$
C $4 \alpha, 3 \beta$
D $3 \alpha, 6 \beta$

Correct answer

B. $3 \alpha, 4 \beta$

Step-by-step solution

{ }_{86} A^{222} \longrightarrow{ }_{84} B^{210}

\begin{aligned} \text{ Decrease in mass number } & =222-210 \\ & =12\end{aligned}

\therefore

Number of

\alpha

-particles emitted

\begin{aligned} & =\frac{12}{4}=3 \\ { }_{86} A^{222} \longrightarrow{ }_{80} X^{210} & \longrightarrow 84 B^{210}\end{aligned}

Increase in atomic number

=84-80=4 \therefore

Number of

\beta

-particles emitted

=4

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