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JIPMER 2004
Exam
JIPMER
Year
2004
Subject
Physics
Chapter
Nuclear Physics

JIPMER 2004 · Physics · Nuclear Physics

The half life of a radioactive substance is 3.6 days. How much of...

The half life of a radioactive substance is 3.6 days. How much of 20 mg of this radioactive substance will remain after 36 days?

Options

  1. A0.0019 mg
  2. B1.019 mg
  3. C1.109 mg
  4. D0.019 mg

Correct answer

D. 0.019 mg

Step-by-step solution

Half life T1/2=3.6T_{1/2}=3.6 days Initial quantity N0=20mgN_0=20 \mathrm{mg} Total time =36=36 days The number of half lives n=tT1/2=363.6=10n=\frac{t}{T_{1/2}}=\frac{36}{3.6}=10 Hence, mass of radioactive substance left after 10 half lives N=N0×(12)n=20×11024=0.019mgN=N_0 \times\left(\frac{1}{2}\right)^n=20 \times \frac{1}{1024}=0.019 \mathrm{mg}
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