In the reaction _1^2 H+ _1^3 H _2^4 He+ _0^1 n , if the binding...

The energy released per nuclear reaction is the resultant binding energy. Binding energy of $\left({ }_1^2 \mathrm{H}+{ }_1^3 \mathrm{H}\right)=a+b$ Binding energy of ${ }_2^4 \mathrm{He}=c$ In a nuclear reaction the resultant nucleus is more stable than the reactants. Hence, binding energy of ${ }_2^4 \mathrm{He}$ will be more than that of $\left({ }_1^2 \mathrm{H}+{ }_1^3 \mathrm{H}\right)$ Thus, energy released per nucleon $$\begin{aligned}& =\text{ resultant binding energy } \& =c-(a+b)=c-a-b\end{aligned}$$