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JIPMER2007PhysicsNuclear Physics

In the reaction ₁^2 H + ₁^3 H ₂^4 He + ₀^1 n , if the binding energies of ₁^2 H , ₁^3 H and ₂^4 He are respectively a, b and c (in MeV ), then the energy (in MeV ) released in this reaction is

Options

  1. Ac+a-b
  2. Bc-a-b
  3. Ca+b+c
  4. Da+b-c

Correct answer

B. c-a-b

Step-by-step solution

The energy released per nuclear reaction is the resultant binding energy. Binding energy of ( ₁^2 H + ₁^3 H )=a+b Binding energy of ₂^4 He =c In a nuclear reaction the resultant nucleus is more stable than the reactants. Hence, binding energy of ₂^4 He will be more than that of ( ₁^2 H + ₁^3 H ) Thus, energy released per nucleon aligned & = resultant binding energy & =c-(a+b)=c-a-b aligned

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