A particle is executing the motion x=a (ω t-θ) . The velocity of the particle is

Correct answer: B. a ω Given equation is x=a (ω t-θ) So, velocity |(d x)/(d t)|=a ω (ω t-θ) At (ω t-θ)=90^ , the velocity will be maximum, therefore the maximum velocity is v=a ω

JIPMER 2005

Exam: JIPMER
Year: 2005
Subject: Physics
Chapter: Oscillations

JIPMER 2005 · Physics · Oscillations

A particle is executing the motion x=a (ω t-θ) . The velocity of...

A particle is executing the motion

x=a \cos (\omega t-\theta)

. The velocity of the particle is

Options

A $a \omega \cos \theta$
B $a \omega$
C $a \omega \sin \theta$
DNone of the above

Correct answer

B. $a \omega$

Step-by-step solution

Given equation is

x=a \cos (\omega t-\theta)

So, velocity

\left|\frac{d x}{d t}\right|=a \omega \sin (\omega t-\theta)

(\omega t-\theta)=90^{\circ}, \quad

the velocity will be maximum, therefore the maximum velocity is

v=a \omega

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