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JIPMER 2011
Exam
JIPMER
Year
2011
Subject
Physics
Chapter
Rotational Motion

JIPMER 2011 · Physics · Rotational Motion

The radius of gyration of a body about an axis at a distance 6 cm...

The radius of gyration of a body about an axis at a distance 6 cm from its centre of mass is 10 cm . Then, its radius of gyration about a parallel axis through its centre of mass will be

Options

  1. A80 cm
  2. B8 cm
  3. C0.8 cm
  4. D80 m

Correct answer

B. 8 cm

Step-by-step solution

From the theorem of parallel axis, the moment of inertia II is equal to I=ICM+Ma2I=I_{\mathrm{CM}}+M a^2 where ICMI_{\mathrm{CM}} is moment of inertia about centre of mass and aa the distance of axis from centre. ∴I=MK2+M×(6)2\therefore \quad I=M K^2+M \times(6)^2 MK12=MK2+36MM K_1^2=M K^2+36 M ⇒K12=K2+36\Rightarrow \quad K_1^2=K^2+36 ⇒(10)2=K2+36\Rightarrow \quad(10)^2=K^2+36 ⇒K2=100−36=64\Rightarrow \quad K^2=100-36=64 ⇒K=8 cm\Rightarrow \quad K=8 \mathrm{~cm}
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