The radius of gyration of a body about an axis at a distance 6 cm from its centre of mass is 10 cm . Then, its radius of gyration about a parallel axis through its centre of mass will be

Step-by-step solution

From the theorem of parallel axis, the moment of inertia I is equal to I=I_ CM +M a^2 where I_ CM is moment of inertia about centre of mass and a the distance of axis from centre. I=M K^2+M (6)^2M K₁^2=M K^2+36 M K₁^2=K^2+36 (10)^2=K^2+36 K^2=100-36=64 K=8 ~cm