JIPMER2010PhysicsRotational Motion
The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing from the edge of the disc and normal to the disc is
Options
- AM R^2
- B1 2 M R^2
- C3 2 M R^2
- D7 2 M R^2
Correct answer
C. 3 2 M R^2
Step-by-step solution
The moment of inertia of uniform circular disc about an axis through its centre and normal to its plane I_ CG = 1 2 M R^2 According to theorem of parallel axis, the moment of inertia of the uniform circular disc about an axis passing from the edge of the disc fand normal to the disc, I=I_ CG +M R^2= 1 2 M R^2+M R^2= 3 2 M R^2