The moment of inertia of a uniform circular disc of radius R and...

The moment of inertia of uniform circular disc about an axis through its centre and normal to its plane $I_{\mathrm{CG}}=\frac{1}{2} M R^2$ According to theorem of parallel axis, the moment of inertia of the uniform circular disc about an axis passing from the edge of the disc fand normal to the disc, $I=I_{\mathrm{CG}}+M R^2=\frac{1}{2} M R^2+M R^2=\frac{3}{2} M R^2$