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JIPMER 2010
Exam
JIPMER
Year
2010
Subject
Physics
Chapter
Thermal Properties of Matter

JIPMER 2010 · Physics · Thermal Properties of Matter

A black body has a wavelength of λ at temperature 2000 K . Its...

A black body has a wavelength of λ\lambda at temperature 2000 K . Its corresponding wavelength at temperature 3000 K will be

Options

  1. A2λ3\frac{2 \lambda}{3}
  2. B3λ2\frac{3 \lambda}{2}
  3. C4λ9\frac{4 \lambda}{9}
  4. D9λ4\frac{9 \lambda}{4}

Correct answer

A. 2λ3\frac{2 \lambda}{3}

Step-by-step solution

According to Wien's displacement law, or λmT=\lambda_m T= constant \text{ constant }oror\quad λ2λ1=T1T2\frac{\lambda_2}{\lambda_1}=\frac{T_1}{T_2} \therefore \quad λ2λ=20003000=23\frac{\lambda_2}{\lambda}=\frac{2000}{3000}=\frac{2}{3}oror\quad \lambda_2=23\frac{2}{3} \lambda
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