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JIPMER 2010
Exam
JIPMER
Year
2010
Subject
Physics
Chapter
Thermal Properties of Matter

JIPMER 2010 · Physics · Thermal Properties of Matter

Consider a compound slab consisting of two different materials...

Consider a compound slab consisting of two different materials having equal lengths, thicknesses and thermal conductivities KK and 2K2 K respectively. The equivalent thermal conductivity of the slab is

Options

  1. A2K\sqrt{2} K
  2. B3K3 K
  3. C43K\frac{4}{3} K
  4. D23K\frac{2}{3} K

Correct answer

C. 43K\frac{4}{3} K

Step-by-step solution

Equivalent thermal conductivity of the compound slab, Keq=l1+l2l1K1+l2K2=l+llK+l2K=2l3l2K=43K\begin{aligned} K_{\mathrm{eq}} & =\frac{l_1+l_2}{\frac{l_1}{K_1}+\frac{l_2}{K_2}}=\frac{l+l}{\frac{l}{K}+\frac{l}{2 K}} \\ & =\frac{2 l}{\frac{3 l}{2 K}}=\frac{4}{3} K \end{aligned}
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