1 kg of water is converted into steam at the same temperature and at 1 atm ( 100 kPa ). The density of water and steam are 1000 kgm ⁻³ and 0.6 kgm ⁻³ respectively. The latent heat of vaporisation of water is 2.25 10^6 Jkg ⁻¹ . What will be

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1 kg of water is converted into steam at the same temperature and at 1 atm ( 100 kPa ). The density of water and steam are 1000 kgm ⁻³ and 0.6 kgm ⁻³ respectively. The latent heat of vaporisation of water is 2.25 10^6 Jkg ⁻¹ . What will be increase in energy?

Quantrex Academy · Accepted Answer

Correct answer: C. 2.08 10^6 ~J

The volume of 1 kg water = 1 100 ~m ^3 and volume of 1 kg steam = 1 0.6 ~m ^3 The increase in volume aligned & = 1 0.6 ~m ^3- 1 1000 ~m ^3 & =(1.7-0.001) m ^3 & 1.7 ~m ^3 aligned The work done by steam is aligned W & =(100 kPa ) (1.7 ~m ^3 ) & =1.7 10^5 ~J aligned The change in intemal energy aligned U & = Q- W & =2.25 10^6 ~J -1.7 10^5 ~J & =208 10^6 ~J aligned

1 kg of water is converted into steam at the same temperature and at 1 atm ( 100 kPa ). The density of water and steam are 1000 kgm ⁻³ and 0.6 kgm ⁻³ respectively. The latent heat of vaporisation of water is 2.25 10^6 Jkg ⁻¹ . What will be increase in energy?

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