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JIPMER 2015
Exam
JIPMER
Year
2015
Subject
Physics
Chapter
Thermodynamics

JIPMER 2015 · Physics · Thermodynamics

For an adiabatic expansion of a mono atomic perfect gas, the volume...

For an adiabatic expansion of a mono atomic perfect gas, the volume increases by 24%24 \%. What is the percentage decrease in pressure?

Options

  1. A24%24 \%
  2. B40%40 \%
  3. C48%48 \%
  4. D71%71 \%

Correct answer

B. 40%40 \%

Step-by-step solution

As we know that pVγ=K∴ΔpVγ+pγVγ−1ΔV=0\begin{aligned} p V^\gamma & =K \\ \therefore \Delta p V^\gamma+p \gamma V^{\gamma-1} \Delta V & =0\end{aligned} ⇒\Rightarrow \quad\left(\frac{\Delta p}{p}\right)=-\gamma(ΔVV)\left(\frac{\Delta V}{V}\right) For monoatomic gas, γ=53\gamma=\frac{5}{3} ∴Δpp=53×24%=40%\therefore \quad \frac{\Delta p}{p}=\frac{5}{3} \times 24 \%=40 \%
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