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AIIMS 201826 May
Exam
AIIMS
Year
2018
Date
26 May
Subject
Chemistry
Chapter
Chemical Equilibrium

AIIMS 2018 · 26 May · Chemistry · Chemical Equilibrium

A vessel of one litre capacity containing 1 mole of SO_3 is heated...

A vessel of one litre capacity containing 1 mole of SO3\mathrm{SO}_3 is heated till a state of equilibrium is attained. 2SO3(g)⇌2SO2(g)+O2(g)2 \mathrm{SO}_{3(g)} \rightleftharpoons 2 \mathrm{SO}_{2(g)}+\mathrm{O}_{2(g)} At equilibrium, 0.6 moles of SO2\mathrm{SO}_2 had formed. The value of equilibrium constant is

Options

  1. A0.180.18
  2. B0.360.36
  3. C0.450.45
  4. D0.680.68

Correct answer

D. 0.680.68

Step-by-step solution

2SO3(g)⇌2SO2(g)+O2(g)2 \mathrm{SO}_{3(g)} \rightleftharpoons 2 \mathrm{SO}_{2(g)}+\mathrm{O}_{2(g)} Inital conc. 1.0 mole 0.0 mole 0.0 mole  Equilibrium 0.4 mole 0.6 mole 0.3 mole ⇒ Equilibrium constant is given by K=[SO2]2[O2][SO3]2=(0.6)2(0.3)(0.4)2=0.675≈0.68\begin{array}{lcl}\text{ Inital conc. } 1.0 \text{ mole } & 0.0 \text{ mole } & 0.0 \text{ mole } \\ \text{ Equilibrium } 0.4 \text{ mole } & 0.6 \text{ mole } & 0.3 \text{ mole } \\ \Rightarrow \text{ Equilibrium constant is given by } \\ K=\frac{\left[\mathrm{SO}_2\right]^2\left[\mathrm{O}_2\right]}{\left[\mathrm{SO}_3\right]^2}=\frac{(0.6)^2(0.3)}{(0.4)^2}=0.675 \approx 0.68\end{array}$$
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