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AIIMS2017ChemistryChemical Equilibrium

For the reaction, H ₂+ I ₂ 2 HI , K =47.6 . If the initial number of moles of each reactant and product is 1 mole then at equilibrium

Options

  1. A[ I ₂ ]= [ H ₂ ], [ I ₂ ]>[ HI ]
  2. B[ I ₂ ]= [ H ₂ ], [ I ₂ ] < [ HI ]
  3. C[ I ₂ ] < [ H ₂ ], [ I ₂ ]=[ HI ]
  4. D[ I ₂ ]> [ H ₂ ], [ I ₂ ]=[ HI ]

Correct answer

B. [ I ₂ ]= [ H ₂ ], [ I ₂ ] < [ HI ]

Step-by-step solution

For the given reaction, K= [ HI ]^2 [ H ₂ ] [ I ₂ ] As 1 mole of H ₂ reacts with 1 mole of I ₂ , even at equilibrium, [ H ₂ ]= [ I ₂ ] Hence, K= [ HI ]^2 [ I ₂ ]^2 or K = [ HI ] [ I ₂ ] = 47.6 i.e., [ HI ]> [ I ₂ ]

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