AIIMS2013ChemistryElectrochemistry
Electrode potential of hydrogen electrode is 18 mV , then [ H ⁺ ] is
Options
- A0.2
- B1
- C2
- D5
Correct answer
C. 2
Step-by-step solution
Given : E_ H ⁺ / H ₂ =18 10⁻³ ~V , [ H ⁺ ]=? Applying Nernst equation, E_ H ⁺ / H ₂ =E_ H ⁺ / H ₂ ^ - 0.0591 1 1 [ H ⁺ ] 18 10⁻³ ~V =0+0.0591 [ H ⁺ ]18 10⁻³ ~V =0.0591 [ H ⁺ ] [ H ⁺ ]=0.3046 [ H ⁺ ]= antilog (0.3046)=2.02=2.0