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AIIMS2013ChemistryElectrochemistry

Electrode potential of hydrogen electrode is 18 mV , then [ H ⁺ ] is

Options

  1. A0.2
  2. B1
  3. C2
  4. D5

Correct answer

C. 2

Step-by-step solution

Given : E_ H ⁺ / H ₂ =18 10⁻³ ~V , [ H ⁺ ]=? Applying Nernst equation, E_ H ⁺ / H ₂ =E_ H ⁺ / H ₂ ^ - 0.0591 1 1 [ H ⁺ ] 18 10⁻³ ~V =0+0.0591 [ H ⁺ ]18 10⁻³ ~V =0.0591 [ H ⁺ ] [ H ⁺ ]=0.3046 [ H ⁺ ]= antilog (0.3046)=2.02=2.0

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