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AIIMS 2008
Exam
AIIMS
Year
2008
Subject
Chemistry
Chapter
Electrochemistry

AIIMS 2008 · Chemistry · Electrochemistry

For the following concentration cell, to be spontaneous (Pt(H_2)...

For the following concentration cell, to be spontaneous (\mathrm{Pt}\left(\mathrm{H}_2\right) P_1) atm. (|\mathrm{HCl}| \mathrm{Pt}\left(\mathrm{H}_2\right) P_2) atm. Which of the following is correct?

Options

  1. AP1=P2P_1=P_2
  2. BP1<P2P_1 < P_2
  3. CP1>P2P_1>P_2
  4. DCan't be predicted

Correct answer

C. P1>P2P_1>P_2

Step-by-step solution

Pt(H2)P1\mathrm{Pt}\left(\mathrm{H}_2\right) \mathrm{P}_1 atm. ∣HCl∣Pt(H2)P2|\mathrm{HCl}| \mathrm{Pt}\left(\mathrm{H}_2\right) \mathrm{P}_2 atm. For spontaneous reaction, Ecell E_{\text{cell }} should be positive so P1>P2Ecell =0.0592log⁡P1P2P_1>P_2E_{\text{cell }}=\frac{0.059}{2} \log \frac{P_1}{P_2} Also, if P1>P2P_1>P_2 oxidation occurs at L.H.S. electrode and reduction occurs at R.H.S. electrode.
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