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AIIMS 2017
Exam
AIIMS
Year
2017
Subject
Chemistry
Chapter
Electrochemistry

AIIMS 2017 · Chemistry · Electrochemistry

On the basis of standard electrode potential of redox couples given...

On the basis of standard electrode potential of redox couples given below, find out which of the following is the strongest oxidising agent. (E∘\left(E^{\circ}\right. values : \mathrm{Fe}^{3+}\left|\mathrm{Fe}^{2+}=+0.77 \mathrm{~V} ;\mathrm{I}_{2(s)}\right|\mathrm{I}−=^{-}= \left.+0.54 \mathrm{~V} ; \mathrm{Cu}^{2+}\left|\mathrm{Cu}=+0.34 \mathrm{~V} ; \mathrm{Ag}^{+}\right| \mathrm{Ag}=+0.80 \mathrm{~V}\right)

Options

  1. AFe3+\mathrm{Fe}^{3+}
  2. BI2(s)\mathrm{I}_{2(s)}
  3. CCu2+\mathrm{Cu}^{2+}
  4. DAg+\mathrm{Ag}^{+}

Correct answer

D. Ag+\mathrm{Ag}^{+}

Step-by-step solution

Higher the electrode potential, better is the oxidising agent. Since, the electrode potential decreases in the order : Ag+∣Ag(+0.80 V)>Fe3+∣Fe2+(+0.77 V)>\mathrm{Ag}^{+}\left|\mathrm{Ag}(+0.80 \mathrm{~V})>\mathrm{Fe}^{3+}\right| \mathrm{Fe}^{2+}(+0.77 \mathrm{~V})> \mathrm{I}_{2(s)}\left|\mathrm{I}^{-}(+0.54 \mathrm{~V})>\mathrm{Cu}^{2+}\right| \mathrm{Cu}(+0.34 \mathrm{~V}) Hence, Ag+\mathrm{Ag}^{+}is the strongest oxidising agent.
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