Which of the following molecules is capable of exhibiting geometrical isomerism?

Step-by-step solution

For a molecule to exhibit geometrical isomerism across a double bond or a ring, each of the two atoms involved in the restricted rotation must be attached to two different groups. Analyzing the given options: (A) 3-Methylbut-1-ene: CH₂=CH-CH(CH₃)₂ The C1 atom of the double bond is attached to two identical hydrogen atoms. Hence, it does not show geometrical isomerism. (B) 2,3-Dimethylbut-2-ene: (CH₃)₂C=C(CH₃)₂ Both C2 and C3 atoms of the double bond are attached to two identical methyl groups. Hence, it does not sh