NEET2026ChemistryChapterActual
Match List I with List II. List I (Molecule) List II (Shape) A PCl₅ I T-shaped B ClF₃ II Trigonal bipyramidal C XeF₂ III Bent D H₂O IV Linear Choose the correct answer from the options given below:
Options
- AA-IV, B-I, C-II, D-III
- BA-II, B-I, C-III, D-IV
- CA-II, B-I, C-IV, D-III
- DA-II, B-IV, C-I, D-III
Correct answer
C. A-II, B-I, C-IV, D-III
Step-by-step solution
For PCl₅ , the central atom P has 5 valence electrons and forms 5 bond pairs with no lone pairs. The hybridization is sp³d and the shape is trigonal bipyramidal. (A II) For ClF₃ , the central atom Cl has 7 valence electrons, forming 3 bond pairs and 2 lone pairs. The hybridization is sp³d and the shape is T-shaped. (B I) For XeF₂ , the central atom Xe has 8 valence electrons, forming 2 bond pairs and 3 lone pairs. The hybridization is sp³d and the shape is linear. (C IV) For H₂O , the central atom O has 6 valence e