At a constant temperature, the Henry's law constants ( K_H ) for four gases W, X, Y, and Z in water are 35 kbar , 0.15 kbar , 76 kbar , and 1.67 kbar respectively. The correct increasing order of their solubility in water at a given partial pressure is:

Step-by-step solution

According to Henry's law, p = K_H x , where p is the partial pressure of the gas, K_H is the Henry's law constant, and x is the mole fraction of the gas in the solution (solubility). At a constant partial pressure, x = p K_H . Thus, solubility is inversely proportional to the Henry's law constant ( K_H ). The given K_H values are: K_H(W) = 35 kbar K_H(X) = 0.15 kbar K_H(Y) = 76 kbar K_H(Z) = 1.67 kbar The decreasing order of K_H values is Y > W > Z > X . Therefore, the increasing order of solubility is Y Answer: Y