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NEET2026ChemistryChapterActual

A hypothetical reaction is observed to be non-spontaneous at low temperatures, but it becomes spontaneous when the temperature is raised significantly. Which of the following conditions correctly describes the enthalpy change ( H ) and entropy change ( S ) for this reaction?

Options

  1. AH < 0 , S < 0
  2. BH > 0 , S > 0
  3. CH 0
  4. DH > 0 , S < 0

Correct answer

B. H > 0 , S > 0

Step-by-step solution

The spontaneity of a reaction is determined by the Gibbs free energy equation: G = H - T S For a reaction to be spontaneous, G must be negative ( G At low temperatures, the magnitude of the T S term is small, so the sign of G is largely determined by H . Since the reaction is non-spontaneous at low temperatures, G > 0 , which implies H > 0 . At high temperatures, the magnitude of the T S term becomes large and dominates the equation. For the reaction to become spontaneous ( G 0 . Therefore, the reaction has H > 0 a

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