An alcohol, whose structure is shown in the figure, is heated with...

The given reactant is 3,3-dimethylbutan-2-ol. When heated with concentrated HI, the reaction proceeds via an $S_N1$ mechanism.

The hydroxyl group is first protonated by HI to form a good leaving group ($-OH_2^+$).

Loss of a water molecule generates a secondary carbocation: $CH_3-C(CH_3)_2-CH^{+}-CH_3$.

To achieve greater stability, this secondary carbocation undergoes a 1,2-methyl shift, rearranging into a more stable tertiary carbocation: $CH_3-C^{+}(CH_3)-CH(CH_3)-CH_3$.

The iodide ion ($I^-$) then acts as a nucleophile and attacks the tertiary carbocation, forming the major product: $CH_3-CI(CH_3)-CH(CH_3)-CH_3$.

The IUPAC name of this major product is 2-iodo-2,3-dimethylbutane.

Answer: 2-Iodo-2,3-dimethylbutane