At a constant temperature, the reaction X₂(g) + 3Y₂(g) 2XY₃(g) has an equilibrium constant K = k and a standard Gibbs free energy change G^ = -z . What will be the standard Gibbs free energy change for the reaction XY₃(g) 1 2 X₂(g) + 3 2 Y₂(g) ?

Step-by-step solution

For the reaction X₂(g) + 3Y₂(g) 2XY₃(g) , the standard Gibbs free energy change is G^ ₁ = -z . The target reaction is XY₃(g) 1 2 X₂(g) + 3 2 Y₂(g) . This reaction is obtained by reversing the first reaction and multiplying it by 1 2 . When a reaction is reversed and multiplied by a factor n , the new standard Gibbs free energy change is given by G^ ₂ = -n G^ ₁ . Here, n = 1 2 . G^ ₂ = - 1 2 (-z) = + z 2 . Answer: +z/2