NEET2026ChemistryChapterActual
Match List I with List II. List I List II A [CoF₆]³⁻ 1 1.73 BM B [Ni(H₂O)₆]²⁺ 2 4.90 BM C [Cu(NH₃)₄]²⁺ 3 0 BM D [Zn(NH₃)₄]²⁺ 4 2.83 BM Choose the correct answer from the options given below.
Options
- AA-4, B-2, C-1, D-3
- BA-2, B-4, C-1, D-3
- CA-2, B-1, C-4, D-3
- DA-3, B-4, C-1, D-2
Correct answer
B. A-2, B-4, C-1, D-3
Step-by-step solution
For [CoF₆]³⁻ , Co is in +3 oxidation state. Co³⁺ has 3d^6 configuration. Since F^- is a weak field ligand, it forms a high spin complex with 4 unpaired electrons. = 4(4+2) = 24 4.90 BM . For [Ni(H₂O)₆]²⁺ , Ni is in +2 oxidation state. Ni²⁺ has 3d^8 configuration. It has 2 unpaired electrons. = 2(2+2) = 8 2.83 BM . For [Cu(NH₃)₄]²⁺ , Cu is in +2 oxidation state. Cu²⁺ has 3d^9 configuration. It has 1 unpaired electron. = 1(1+2) = 3 1.73 BM . For [Zn(NH₃)₄]²⁺ , Zn is in +2 oxidation state. Zn²⁺ has 3d¹⁰ configuration.