Two half cell reactions are given below : Au ³⁺ + 3 e ⁻ Au ( s ), E ^ _ Au / Au ³⁺ = -1.50 ~V 3 Ni ²⁺ + 6 e ⁻ 3 Ni ( s ), E ^ _ Ni / Ni ²⁺ = +0.25 ~V The standard EMF of a cell with feasible redox reaction will be :

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Quantrex Academy · Accepted Answer

Correct answer: C. +1.75 ~V

Given the standard oxidation potentials: E ^ _ Au / Au ³⁺ = -1.50 ~V E ^ _ Au ³⁺/ Au = +1.50 ~V E ^ _ Ni / Ni ²⁺ = +0.25 ~V E ^ _ Ni ²⁺/ Ni = -0.25 ~V For a feasible redox reaction, the standard cell potential E ^ _ cell must be positive. The half-cell with the higher standard reduction potential acts as the cathode, and the one with the lower standard reduction potential acts as the anode. E ^ _ cell = E ^ _ cathode - E ^ _ anode E ^ _ cell = 1.50 - (-0.25) = +1.75 ~V Answer: +1.75 ~V

Two half cell reactions are given below : Au ³⁺ + 3 e ⁻ Au ( s ), E ^ _ Au / Au ³⁺ = -1.50 ~V 3 Ni ²⁺ + 6 e ⁻ 3 Ni ( s ), E ^ _ Ni / Ni ²⁺ = +0.25 ~V The standard EMF of a cell with feasible redox reaction will be :

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