Match List I with List II : List I List II A HCN I 5 bonds B XeF ₄ II 3 bonds, 1 bond C PCl ₅ III 4 bonds, 2 lone pairs D H ₂ CO IV 2 bonds, 2 bonds Choose the correct answer from the options given below :

Step-by-step solution

For HCN , the structure is H - C N . It contains 2 bonds and 2 bonds. Thus, A matches with IV. For XeF ₄ , the central atom Xe has 8 valence electrons. It forms 4 bonds with four fluorine atoms and has 2 lone pairs of electrons. Thus, B matches with III. For PCl ₅ , the central atom P has 5 valence electrons. It forms 5 bonds with five chlorine atoms and has no lone pairs. Thus, C matches with I. For H ₂ CO , the structure is H ₂ C = O . It contains 3 bonds (two C - H and one C - O ) and 1 bond ( C = O ). Thus, D m