NEET2026ChemistryChapterActual
Match List I with List II : List I List II A [ Ni ( CO )₄] I Octahedral B [ Ni ( CN )₄]²⁻ II Linear C [ Co ( en )₃]³⁺ III Tetrahedral D [ Ag ( NH ₃)₂]^+ IV Square planar Choose the correct answer from the options given below :
Options
- AA-IV, B-III, C-I, D-II
- BA-III, B-IV, C-I, D-II
- CA-III, B-IV, C-II, D-I
- DA-I, B-II, C-III, D-IV
Correct answer
B. A-III, B-IV, C-I, D-II
Step-by-step solution
For [ Ni ( CO )₄] , Ni is in the 0 oxidation state with an electronic configuration of 3d^8 4s^2 . Since CO is a strong field ligand, the 4s electrons are forced to pair up in the 3d orbitals, resulting in a 3d¹⁰ configuration. The hybridization is sp^3 , giving a tetrahedral geometry. Thus, A matches III. For [ Ni ( CN )₄]²⁻ , Ni is in the +2 oxidation state with a 3d^8 configuration. CN ^- is a strong field ligand, causing the pairing of 3d electrons and leaving one 3d orbital empty. The hybridization is dsp^2 ,